The mole fraction of a solute in a 100 molal aqueous solution is _____$\times {10}^{-2}$. (Round off to the Nearest Integer)

100 molal solution indicates that 100 moles of solute present in 1 kg of solvent, which is water. (or 1000 g of solvent).

$$\begin{gathered} \mathrm{mole} \mathrm{fraction} \mathrm{of} \mathrm{solute}=\frac{\mathrm{moles} \mathrm{of} \mathrm{solute}}{\mathrm{moles} \mathrm{of} \mathrm{solute}+\mathrm{mole} \mathrm{of} \mathrm{solvent}} \\ \mathrm{mole} \mathrm{fraction} \mathrm{of} \mathrm{solute}=\frac{100}{100+{\displaystyle \frac{1000}{18}}} \\ \mathrm{moles} \mathrm{fraction} \mathrm{of} \mathrm{solute}\cong 64\times {10}^{-2} \end{gathered}$$