The mole fraction of a solute in carbon tetrachloride is 0.235. The molality of the solution is about

Let Amount of solute= 0.235 mol; Amount of solvent= (1 - 0.235) mol = 0.765 mol Mass of solvent, $m=n{M}_{\mathrm{m}}=\left(0.765\mathrm{mol}\right)\left(154\mathrm{g}{\mathrm{mol}}^{-1}\right)=117.81\mathrm{g}$

Molality of solution $=\frac{n}{m}=\frac{0.235\mathrm{mol}}{117.81\times {10}^{-3}\mathrm{kg}}=2.0\mathrm{mol}{\mathrm{kg}}^{-1}$