Q.

The mole fraction of glucose in water is 0.2. The molality of the solution will be

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a

10.2 mol kg-1

b

16.6 mol kg-1

c

14.2 mol kg-1

d

12.4 mol kg-1

answer is C.

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Detailed Solution

Mole fraction of glucose= 0.2 implies that

Amount of glucose, n2 = 0.2 mol;    Amount of water, n1 = 0.8 mol

Mass of water, m1=n1M1=(0.8mol)18gmol1=14.4g=14.4×103kg

Molality of solution, m=n2m1=0.2mol14.4×103kg=14.18molkg1

 

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