The mole fraction of O₂ in air is 0.2. The number of moles of O₂ from air dissolved in 100 moles of water at 298K and 10 atm pressure is : (Given Henry's law constant for the solubility of O₂ gas in water is 4.0 x 10⁴ atm.)

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5 x 10^-3

2 x 10^-3

4 x 10^-2

2.5 x 10^-2

answer is A.

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Detailed Solution

$P_{O_{2}} = {(K_{H})}_{O_{2}} \times \frac{n_{O_{2}}}{100} \begin{aligned} 0 .2 \times 10 = 4 \times 10^{4} \times \frac{n_{O_{2}}}{100} \\ n_{O_{2}} = 5 \times 10^{- 3} mol \end{aligned}$

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