The mole fraction of solute in an aqueous solution is $\frac{1}{112}$. The molality (m) of the solution is______ ${\mathrm{molL}}^{-1}$

Given, mole fraction of aqueous solution = $\frac{1}{112}$

 Let the mole of the aqueous solution is 1

X_b= $\frac{1}{112}$

X_a = $1-\frac{1}{112}=\frac{111}{112}$

Ma = molar mass of solvent = 18g

$\mathrm{Molality}=\frac{{\mathrm{X}}_{\mathrm{b}}\times 1000}{{\mathrm{X}}_{\mathrm{a}}\times {\mathrm{M}}_{\mathrm{a}}}=\frac{\frac{111}{112}\times 1000}{\frac{1}{112}\times 18}=0.5 \mathrm{m}$

Therefore, molality of solution is 0.5m.