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The mole percentage of oxygen in a mixture of 7 gm of Nitrogen and 8 gm of oxygen is

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answer is D.

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Detailed Solution

Number of moles of N₂=weight/molecular weight=7/28 = 0.25

moles of O₂=weight/molecular weight=8/32 = 0.25

Thus, mole % of O₂= [moles of O₂/(moles of O₂+moles of N₂)] *100

=[0.25/(0.25+0.25) ]*100= 50%

Hence, option(D) 50 is correct.

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