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The molecular formula of a commercial resin used for exchanging ions in water softening is $C_{10} H_{9} S O_{3} N a (m o l . w t = 232) .$ What would be the maximum uptake of $C a^{2 +}$ ions by the resin when expressed in mole per gram resin?

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$\frac{1}{116}$

$\frac{1}{232}$

$\frac{2}{309}$

$\frac{1}{464}$

answer is D.

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Detailed Solution

$2 C_{10} H_{9} S \bar{O_{3}} N \overset{\oplus}{a} + C \overset{2 +}{a} \to {(C_{10} H_{9} S O_{3})}_{2} C a + 2 N \overset{\oplus}{a}$

2 mole 1 mole

$2 \times 232$

$= 464 g$ 1 mole
$1 g$ $\frac{1}{464} m o l e g^{- 1}$ of resin

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