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The molecular formula of a commercial resin used for exchanging ions is water softening is $C_{8} H_{7} S O_{3}^{-} N a^{+}$ (molar mass:206). What would be the maximum uptake of $C a^{+ 2}$ ions by the resin when expressed in mole per gram resin

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$\frac{2}{309}$

$\frac{1}{412}$

$\frac{1}{103}$

$\frac{1}{206}$

answer is B.

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Detailed Solution

$2 C_{8} H_{7} S O_{3}^{-} N a^{+} + C a^{+ 2} \overset{}{\to} {(C_{8} H_{7} S O_{3})}_{2} C a + 2 N a^{+}$

2 mole of water softener requires 1 mole of $C a^{+ 2}$ ion

So,1 mole of water softener requires 1/2 mole of $C a^{+ 2}$ ion

Thus $\frac{1}{2 \times 206} = \frac{1}{412}$ mol/gm will be maximum uptake.

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