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The molecular formulas of various hexacordinates are given as below.
(a) CrCl₃.6NH₃ (b) CrCl₃.5NH₃
(c) CrCl₃.4NH₃
If the number of NH₃ ligands attached to the central metal ion respectively are 6, 5 and 4, then the number of Cl^-ions showing dual character in (a), (b) and (c) respectively are:

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3, 3, 3

0, 1, 2

3, 2, 1

6, 5, 4

answer is B.

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Detailed Solution

Dual character of the above complexes are 0, 1, 2 respectively.
$[Cr {({NH}_{3})}_{6}] {Cl}_{3}, [Cr {({NH}_{3})}_{5} Cl] {Cl}_{2}, [Cr {({NH}_{3})}_{4} {Cl}_{2}] Cl$

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