The molecular shapes of SF4 , CF4 and XeF4 are

Number of valence electrons in SF4 = 6 + 4 x 7 = 34. These are distributed as follows.There are five paired of electrons around S. The shape of SF4 will be trigonal bipyramide with one lone pair of electrons on the S atom.Number of Valence electrons in CF4 = 4 + 4 x 7 = 32. These are distributed as follows.There are four paired of electrons around C. The shape of CF4 is tetrahedral. There is no lone pair of electrons on the C atom.Obviously the choice b is correct. The molecule of XeF4 will have different geometry with two lone pairs of electrons on Xe atom. There are 36 (= 8 + 4 x 7) valence electrons and these are distributed as follows.The shape of XeF4 will be square planar.

The molecular shapes of SF4 , CF4 and XeF4 are

Number of valence electrons in SF4 = 6 + 4 x 7 = 34. These are distributed as follows.There are five paired of electrons around S. The shape of SF4 will be trigonal bipyramide with one lone pair of electrons on the S atom.Number of Valence electrons in CF4 = 4 + 4 x 7 = 32. These are distributed as follows.There are four paired of electrons around C. The shape of CF4 is tetrahedral. There is no lone pair of electrons on the C atom.Obviously the choice b is correct. The molecule of XeF4 will have different geometry with two lone pairs of electrons on Xe atom. There are 36 (= 8 + 4 x 7) valence electrons and these are distributed as follows.The shape of XeF4 will be square planar.

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

The molecular shapes of SF⁴ , CF⁴ and XeF⁴ are

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

the same with 2,0 and 1 lone pairs of electrons on the central atom, respectively

different with 0,1 and 2 lone pairs of electrons on the central atom, respectively

the same with 1, 1 and 1 lone pair of electrons on the central atom, respectively

different with 1,0 and 2 lone pairs of electrons on the central atom, respectively

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

Number of valence electrons in SF₄ = 6 + 4 x 7 = 34. These are distributed as follows.

There are five paired of electrons around S. The shape of SF₄ will be trigonal bipyramide with one lone pair of electrons on the S atom.

Number of Valence electrons in CF₄ = 4 + 4 x 7 = 32. These are distributed as follows.

There are four paired of electrons around C. The shape of CF₄ is tetrahedral. There is no lone pair of electrons on the C atom.

Obviously the choice b is correct. The molecule of XeF₄ will have different geometry with two lone pairs of electrons on X_eatom. There are 36 (= 8 + 4 x 7) valence electrons and these are distributed as follows.

The shape of XeF₄ will be square planar.

Watch 3-min video & get full concept clarity