The molecular shapes of SF⁴ , CF⁴ and XeF⁴ are

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the same with 2,0 and 1 lone pairs of electrons on the central atom, respectively

different with 0,1 and 2 lone pairs of electrons on the central atom, respectively

the same with 1, 1 and 1 lone pair of electrons on the central atom, respectively

different with 1,0 and 2 lone pairs of electrons on the central atom, respectively

answer is B.

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Detailed Solution

Number of valence electrons in SF₄ = 6 + 4 x 7 = 34. These are distributed as follows.

There are five paired of electrons around S. The shape of SF₄ will be trigonal bipyramide with one lone pair of electrons on the S atom.

Number of Valence electrons in CF₄ = 4 + 4 x 7 = 32. These are distributed as follows.

There are four paired of electrons around C. The shape of CF₄ is tetrahedral. There is no lone pair of electrons on the C atom.

Obviously the choice b is correct. The molecule of XeF₄ will have different geometry with two lone pairs of electrons on X_eatom. There are 36 (= 8 + 4 x 7) valence electrons and these are distributed as follows.

The shape of XeF₄ will be square planar.

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