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Q.

The Molecular weight of a gas is 40. At 400K if 120 g of this gas has a volume of 20 litres, the pressure of the gas in atm is

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a

0.546

b

4.92

c

5.02

d

49.6

answer is A.

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Detailed Solution

Given

$T = 400 K$

V=20L

$n = \frac{120}{40} = 3 moles$

P=?

$p = \frac{nRT}{V}$

$P = \frac{3 \times 0.0821 \times 400}{20}$

P=4.92 atm

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