The molecular weight of  oxide of an element is 44. The equivalent weight of the element is 14. The atomic weight of the element is

Formula of oxide ${\mathrm{M}}^{\mathrm{x}}{\mathrm{O}}^2$

                             ${\mathrm{M}}_2{\mathrm{O}}_{\mathrm{x}}$

Molecular weight of oxide = $2(\mathrm{At}.\mathrm{wt}\mathrm{of}\mathrm{M})+\mathrm{x}\times 16$

$\begin{array}{l}44=2\times \mathrm{Eq}.\mathrm{wt}\times \mathrm{x}+16\mathrm{x}\\ 44=28\mathrm{x}+16\mathrm{x}=44\mathrm{x};\mathrm{x}=1\\ \therefore \mathrm{At}.\mathrm{wt}=\mathrm{Eq}.\mathrm{wt}\times \mathrm{x}=14\times 1=14\end{array}$