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Q.

The molecular weights of two ideal gases A and B are respectively 100 and 200.One gram of A occupies V litres of volume at STP. What is the volume (in litres) occupied by one gram of B at STP?

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a

V/2

b

2V

c

V2

d

V

answer is A.

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Detailed Solution

Number of moles are

So, 

nA=1100

and 

nB=1200

Under identical conditions of temperature and pressure

VAVB=nAnB

VAVB=1/1001/200

VB=V/2

Hence the required answer is A

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