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Q.

The molecule with trigonal pyramidal geometry is

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a

PCl5

b

SF4

c

ClF3

d

XeF2

answer is A.

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Detailed Solution

Number of electron pairs(EP)=V+M-C+A2; V=Group number of central atom; M=-H, -X, -OH....monovalent groups attached to central atom ; C=Charge of cation ; A=Charge of anion ; V=5,6,7,8 respectively for 15th, 16th,  17th, 18th group elements ; Number bond pairs, BP(according to VSEPR theory)=Number of atoms directly attached to central atom;                                                                                             =5,4,3,2 respectively in PCl5, SF4, ClF3, XeF2 ; Number lone pairs on central atom(LP)=EP-BP ;                                                                      =0,1,2,3 respectively in PCl5, SF4, ClF3, XeF2; PCl5-'5' bp +'0' lp ; sp3d-Trigonal bipyramidal ; SF4-'4' bp +'1' lp ; sp3d-Distorted tetrahedral (or) see-saw (or) Z-shape ; ClF3-'3' bp +'2' lp ; sp3d-Bent T-shape ; XeF2-'2' bp +'3' lp ; sp3d-Linear ; Note; Each bonded halogen atom has '3' lone pairs on it ;  

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