The moment of inertia of a door of mass m, length 2 $l$ and width $l$ about its longer side is

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$\frac{11 {ml}^{2}}{24}$

$\frac{5 {ml}^{2}}{24}$

$\frac{{ml}^{2}}{3}$

none of these

answer is C.

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Detailed Solution

(About YY ' ) $= \frac{{ml}^{2}}{12}$
Using parallel axis theorem
$I (about AD) = \frac{{ml}^{2}}{12} + \frac{{ml}^{2}}{4} = \frac{{ml}^{2}}{3}$
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