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Q.

The moment of inertia of a ring of mass $M$ and radius $R$ about $P Q$ axis will be :-

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a

$M R^{2}$

b

$\frac{M R^{2}}{2}$

c

$2 M R^{2}$

d

$\frac{3}{2} M R^{2}$

answer is C.

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Detailed Solution

Question Image

Applying parallel axis theorem

$I_{P Q} = I_{C} + M d^{2} \Rightarrow I_{P Q} = \frac{M R^{2}}{2} + M {(R)}^{2} = \frac{3}{2} M R^{2}$

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The moment of inertia of a ring of mass M and radius R about PQ axis will be :-