The moment of inertia of a semicircular ring about an axis, passing through the center and perpendicular to the plane of ring, is 1xMR2, where R is the radius and M is the mass of the semicircular ring. The value of x will be _.

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The moment of inertia of a semicircular ring about an axis, passing through the center and perpendicular to the plane of ring, is $\frac{1}{x} {MR}^{2}$ , where R is the radius and M is the mass of the semicircular ring. The value of x will be _.

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answer is 1.

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In case of ring,
$I = {MR}^{2} so x = 1$

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