The moment of inertia of a semicircular ring about an axis, passing through the center and perpendicular to the plane of ring, is 1xMR2, where R is the radius and M is the mass of the semicircular ring. The value of x will be _.

Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

The moment of inertia of a semicircular ring about an axis, passing through the center and perpendicular to the plane of ring, is $\frac{1}{x} {MR}^{2}$ , where R is the radius and M is the mass of the semicircular ring. The value of x will be _.

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 1.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

In case of ring,
$I = {MR}^{2} so x = 1$

Watch 3-min video & get full concept clarity

JEE

NEET

Foundation JEE

Foundation NEET

CBSE