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Q.

The moment of inertia of a wheel about the axis of rotation is 3MKS units. Its kinetic energy will be 600 joule if the period of rotation (in s) is ; $(π = 3.14)$

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answer is 0.31.

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Detailed Solution

K.E. $= \frac{1}{2} {Iω}^{2}$

$ω = \sqrt{\frac{2 K . E}{1}} - \sqrt{\frac{2 \times 600}{3}} = 20 rad / s$

$ω = \frac{2 π}{T} = 20 \Rightarrow T = \frac{π}{10} s$

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