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Q.

The moment of inertia of a wheel of radius 20 cm is 40kg m2 . If a tangential force of 80 N applied on the wheel. Its rotational K.E. after 4s is

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a

16.2 J 

b

51.2J

c

25.6J

d

24.8J

answer is B.

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Detailed Solution

τ=rF=0.2×80=16N−mα=τI=1640=25rad/s2
KE gained in 4s is E=12Iω2=12I(αt)2=12(40)25×42=51.2J

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