The moment of inertia of an uniform circular disc about its central axis is ‘ $I$ ’. Its moment of inertia about a tangent in its plane is equal to $\frac{x}{2}I$  , then x is___

Moment of inertia of an uniform circular ring about its central axis is ‘I’

here $I=M{R}^2$

Moment of inertia of an uniform circular ring about its diameter, $\frac{M{R}^2}{2}$

Moment of inertia about a tangent in its plane is $\frac{M{R}^2}{2}+M{R}^2=3\frac{M{R}^2}{2}=\frac{3}{2}I$