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The moment of inertia of a body about a given axis is 1.2 kgm². Initially the body is at rest. In order to produce a rotational kinetic energy of 1500 joule, an angular acceleration of 25 rad/sec² must be applied about that axis for a duration of

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Detailed Solution

\large {\omega _f} = \alpha t \Rightarrow t = \frac{{{\omega _f}}}{\alpha }

\large \frac{1}{2}I{\omega ^2} = K.E \Rightarrow \frac{1}{2} \times 1.2{\omega ^2} = 1500

\large {\omega ^2} = \frac{{1500}}{{0.6}} = 2500 \Rightarrow \omega = 50rad/s

\large \therefore t = \frac{\omega }{\alpha } = \frac{{50}}{{25}} = 2s

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