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The momentum of photon of energy 1 MeV will approximately be

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3 × 10^-6 kg-m/s

5 x 10^-22 kg-m/s

10^-22 kg-m/s

answer is B.

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Detailed Solution

$P = \frac{E}{C} = \frac{{1 \times {{10}^6} \times 1.6 \times {{10}^{ - 19}}}}{{3 \times {{10}^8}}}\,;\,\,$

$\therefore P = 5 \times {10^{ - 22}}\,kg-m/s$

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