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Q.

The monochromatic beam of light is incident at 60o on one face of an equilateral prism of refractive index n and emerges from the opposite face making an angle θ(n) with the normal (see the figure). For n=3 the value of θ is 60o and dn=m. The value of m is

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answer is 2.

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Detailed Solution

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sinθ=nsinr10=ncosr1dr1dn+sinr1dr1dn=sinr1ncosr1 Also, r2+r1=Adr2dA=dr1dA Also, nsinr2=sinθ1×sinr2+ncosr2dr2dn=cosθdnsinr2+ncosr2×sinr1ncosr1=cosθdn12+12=12dndn=2

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The monochromatic beam of light is incident at 60o on one face of an equilateral prism of refractive index n and emerges from the opposite face making an angle θ(n) with the normal (see the figure). For n=3 the value of θ is 60o and dθdn=m. The value of m is