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Q.

The most common oxidation state of Lanthanoid elements is +3. Which of the following is likely to deviate easily from +3 oxidation state?

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a

$La (At . No . 57)$

b

$Lu (At . No . 71)$

c

$Gd (At . No . 64)$

d

$Ce (At . No . 58)$

answer is A.

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Detailed Solution

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$Ce = [Xe] 4 f^{1} 5 d^{1} 6 s^{2}$

${Ce}^{3 +} = [Xe] 4 f^{1} 5 d^{0}$

${Ce}^{+ 4} = [Xe] 4 f^{0} 5 d^{0} (Noble gas configuration)$

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