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Q.

The motion of a particle along a straight line is given by $v^{2} = u^{2} + 90 s$ If the particle starts from rest, then the acceleration is

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a

$45 {units/sec}^{2}$

b

$15 {units/sec}^{2}$

c

$30 {units/sec}^{2}$

d

$75 {units/sec}^{2}$

answer is C.

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Detailed Solution

$V^{2} = u^{2} + 90 s$

$\Rightarrow 2 V \cdot a = 90 \frac{d s}{d t} (∵ u = 0) \Rightarrow a = 45$

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