The multiplication is $2A\times A=B6$. Find the value of A and B.

[Note: Here A and B are digits.]

Given: $2A\times A=B6$

The above multiplication can also be written as:

On putting $A=1, 2, 3, 4, 5$ and so on, we get,

$4\times 4=16$, in which the one's place is 6, and the carry is 1.

Therefore, $A=4$

For $B:$

$2\times A+1=B$

$\Rightarrow B=2\times 4+1$

$\Rightarrow B=9$

Hence, the value of A and B are: $A=4, B=9$