The n rows each containing m cells in series are joined in parallel. Maximum current is taken from this combination across an external resistance of $3 Ω$ resistance. If the total number of cells used are 24 and internal resistance of each cell is $0.5 Ω$ then

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m = 12, n = 2

m = 2, n = 12

m = 8, n = 3

m = 6, n = 4

answer is C.

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Detailed Solution

Total cells = m x n = 24 (i)
For maximum current in the circuit $R = \frac{m r}{n}$
$\Rightarrow 3 = \frac{m}{n} \times (0.5) \Rightarrow m = 6 n (i i)$
On solving Eqs. (i) and (ii), we get m = 12, n = 2

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