The near point of a hypermetropic eye is 1m then the nature and power of the lens required to correct this defect

Given that near point of hypermetropic eye is 1m 

d = 1 m = 100 cm

for correction, the focal length of convex lens needed will be 

$\mathrm{f}=\frac{25\mathrm{d}}{\mathrm{d}-25}=\frac{25\times 100}{100-25}=\frac{25\times 100}{75}=\frac{100}{3}\mathrm{cm}$

$\mathrm{P}=\frac{100}{\text{ fincm }}=\frac{100}{100/3}=+3\mathrm{D}$

$\mathrm{P}=+3\mathrm{D}$

we require convex lens of power + 3D