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The near point of a hypermetropic person is 50 cm from the eye. What is the power of the lens required to enable the person to read clearly a book held at 25 cm from the eye

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answer is A.

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Detailed Solution

$\begin{array}{l} \frac{1}{f} = \frac{1}{v} - \frac{1}{u}; u = - 25 cm, v = - 50 cm \\ f = 50 cm, P = \frac{100}{f (cm)}; P = \frac{100}{50 (cm)} \Rightarrow P = 2 D \end{array}$

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