AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

The near point of a hypermetropic person is $50 cm$ from the eye. Which of the following is correct for the power of the lens required to enable the person to read clearly a book held at $25 cm$ from the eye?

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

3 D

2 D

2.5 D

3.2 D

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

The power of the lens required is

2 D

.
Given,
Image distance,

v = - 50 cm

and object distance,

u = - 25 cm

.
Form the lens formula,

\frac{1}{f} = \frac{1}{v} - \frac{1}{u}

Where

f

v

, and

u

are the focal length, image distance, and object distance, respectively.
On substituting the given values, we get the focal length as

\Rightarrow \frac{1}{f} = \frac{1}{- 50} - \frac{1}{(- 25)}

\Rightarrow \frac{1}{f} = \frac{1}{50}

\Rightarrow f = 50 cm

Hence, the focal length is

50 cm

.
It is known that the power of a lens is the reciprocal of the focal length of the lens. Mathematically,

P = \frac{100}{f}

Where

f

is the focal length of the lens in centimetres.
On substituting the given values, we get the power as

\Rightarrow P = \frac{100}{50}

\Rightarrow P = 2 D

Hence, the required power of the lens is

2 D

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!