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The near point of a hypermetropic person is $75 cm$ from the eye. Which of the following options is correct for the focal length of the lens required?

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\frac{3}{8} m

6 / 5 m

9 / 2 m

3 / 2 m

answer is A.

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Detailed Solution

The focal length of the lens required is

\frac{3}{8} m

.
Given,
Image distance,

v = - 75 cm

and object distance,

u = - 25 cm

.
Form the lens formula,

\frac{1}{f} = \frac{1}{v} - \frac{1}{u}

Where

f

v

, and

u

are the focal length, image distance, and object distance, respectively.
On substituting the given values, we get the focal length as

\Rightarrow \frac{1}{f} = \frac{1}{- 75} - \frac{1}{(- 25)}

\Rightarrow \frac{1}{f} = \frac{2}{75}

\Rightarrow f = 37.5 cm or \frac{3}{8} m

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