The Nernst equation giving dependence of electrode potential on concentration is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

$E = E^{0} - \frac{2 .303 RT}{nF} \log \frac{[M^{n +}]}{[M]}$

$E = E^{0} + \frac{2 .303 RT}{nF} \log \frac{[M^{n +}]}{[M]}$

$E = E^{0} + \frac{2 .303 RT}{nF} \log \frac{[M]}{[M^{n +}]}$

$E = E^{0} - \frac{2 .303 RT}{nF} \log [M^{n +}]$

answer is B.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

The Nernst equation for the single electrode is given as

$M^{n +} + n e^{-} \to M E_{c e l l} = E_{c e l l}^{o} + \frac{0.0591}{n} \log [M^{n +}]$

Watch 3-min video & get full concept clarity

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test