The network shown in figure is part of the some bigger circuit. Charge on capacitor  $(C=1F)$  at any time $t$ is $q=3(2-e^{-t})$  in coulombs. If at  $t=0$ the potential of points A and B is 20 V each, then at   $t=0$ choose the correct statements

At $t=0$,                              $q=3C,i_{Ap}=\frac{dq}{dt}=3A,V_C=\frac{q}{C}=3V$
 
Potential drop across capacitor C=3V
Potential drop across resistor = (1x3) = 3V
$\therefore$Potential at point   $P\left(V_P\right)=20-(3+3)=14V$
 $\therefore V_P-0=14V$
Now, current through R is given by
 
$i=\frac{V_P-0}{R}=\frac{14}{2}=7A$