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The network shown in the figure is a part of a complete circuit. If at a certain instant the current of 5 A is flowing from A to B and is decreasing at the rate of $10^{3} A / s$ then $V_{A} - V_{B}$ is

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15 V

$- 5 V$

$- 15 V$

5 V

answer is C.

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Detailed Solution

$V_{A} - (5 \times 1) + 15 + L . \frac{d i}{d t} = V_{B}$

$V_{A} - V_{B} = - 15$

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