The network shown in the figure is a part of a complete circuit. If at a certain instant the current i is 5 A and is decreasing at the rate of $10^{3} A / s$ then $V_{B} - V_{A} is$

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5 V

10 V

15 V

20 V

answer is C.

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Detailed Solution

By using Kirchhoff's voltage law,

$V_{A} - iR + E - L \frac{di}{dt} = V_{B} \Rightarrow V_{B} - V_{A} = - 5 \times 1 + 15 - 5 \times 10^{- 3} \times (- 10^{3}) v o l t T h e r e f o r e v_{B} - v_{A} = 15 v o l t .$

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