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Q.

The no of photons of light of wavelength $7000 \overset{0}{A}$ equivalent to 1J are

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a

$100000$

b

$3.52 \times 10^{18}$

c

$3.52 \times 10^{- 18}$

d

$50, 000$

answer is B.

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Detailed Solution

According to plank’s theory

$E = \frac{nhc}{λ}$

$n = \frac{1 \times (7000 \times 10^{- 10} m)}{(3 \times 10^{8} {ms}^{- 1}) (6.62 \times 10^{- 34})} = 3.52 \times 10^{18}$

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