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The non-repeated root of $x^{3} + 4 x^{2} + 5 x + 2 = 0$ is

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- 1

- 2

- \frac{5}{3}

answer is B.

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Detailed Solution

x^{3} + 4 x^{2} + 5 x + 2 = 0

$(x + 1) (x^{2} + 3 x + 2) = 0$

$(x + 1) (x + 2) (x + 1) = 0$

$x = - 1, - 2, - 1$

$∴$ So non-repeated root is $- 2$ .

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