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Q.

The normal at a point bt12 ,2bt1 on a parabola meets the parabola again at the point bt22, 2bt2 then

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a

t2=-t1+2t1

b

t2=t1+2t1

c

t2=-t1-2t1

answer is D.

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Detailed Solution

Equation of normal at b t12, 2bt1 for y2=4ax is t1x+y=2bt1+bt13 it is also passing through b t22, 2bt2

 

t1bt22+2bt2=2bt1+bt13 bt1t22+2bt2=2bt1+bt13 bt1t22-bt13=2bt1-2bt2 bt1t22-t12=2bt1-t2 -t1t1+t2=2 t2=-t1-2t1     

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