The normal boiling point of a liquid X is 400 K. Which of the following statement is true about the process, $\mathrm{X}\left(\mathrm{l}\right)\stackrel{ }{\to }\mathrm{X}\left(\mathrm{g}\right)?$

At 400 K, system is in equilibrium and at equilibrium point, $\mathrm{\Delta G}=0$. Therefore, at 400 $\mathrm{\Delta G}=0$ 
At 400 K and 2 atm pressure, the system has boiling point more than 400 K, so at this point the system will be non- spontaneous, $\mathrm{\Delta G}=+\mathrm{ve}$.
At 400 K and 0.1 atm pressure, the system has boiling point less than 400 K, so at this point the system will be spontaneous, $\mathrm{\Delta G}=-\mathrm{ve}$.