The normal density of a material is $ρ$ and its bulk modulus of elasticity is K. The magnitude of increase in density of material, when a pressure P is applied uniformly on all sides, will be:

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

$\frac{ρ P}{K}$

$\frac{ρ K}{P}$

$\frac{P K}{ρ}$

$\frac{K}{ρ P}$

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$\begin{array}{l} Mass = density \times volume \\ \Rightarrow m = ρ V \\ \Rightarrow 0 = ρ d V + V d ρ \\ \Rightarrow d ρ = - ρ \frac{d V}{V} \\ Also, Bulk Modulus = K = - \frac{d P}{\frac{d V}{V}} \\ \Rightarrow \frac{d V}{V} = - \frac{d P}{K} \\ Thus, d ρ = ρ \frac{d P}{K} \\ here d P = P (given) \\ \Rightarrow Increase in density = d ρ = ρ \frac{P}{K} \end{array}$