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Q.

The normal to the curve $x^{2} + 2 x y - 3 y^{2} = 0$ at $(1, 1)$ is

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a

1) does not meet the curve again

b

meets the curve, again in the second quadrant

c

meets the curve, again in third quadrant

d

meets the curve, again in fourth quadrant

answer is D.

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Detailed Solution

Slope of Tangent $m = 1$

Normal is $y - 1 = - 1 (x - 1)$

$\Rightarrow$ sub in given curve $\Rightarrow$ $x = 3, y = - 1$

The point lies in $" Q_{4} "$

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