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Q.

The normality and volume strength of a solution made by mixing 1.0L each of 5.6 volume and 11.2 volume H₂O₂ solution are

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a

1n; 8.4 vol

b

1.5N; 8.4 vol

c

1.5N; 5.6 vol

d

1N, 5.6 vol

answer is B, C.

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Detailed Solution

VS = 5.6 × N
$N = \frac{N_{1} V_{1} + N_{2} V_{2}}{V_{1} + V_{2}} = \frac{1 x 1 + 2 x 1}{1 + 1} = \frac{3}{2} = 1.5 N$
VS = 5.6 × 1.5 = 8.4 vol

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