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The Normality of 0.98% (w/v) H₂SO₄ solution is

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0.2N

0.1N

answer is C.

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Detailed Solution

\begin{array}{l} N = \frac{{10X\left( {\frac{W}{V}} \right)\% }}{{GEW\,of\,{H_2}S{O_4}}}\\ N = \frac{{10X0.98}}{{49}}\\ {N_{{H_2}S{O_4}}} = 0.2N \end{array}

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