The Normality of 0.98%(wV) H2SO4 solution is

Normality=%×10Eq.wtN=0.98×1049N=0.2 Sulphuric acid M.wt=98, E.Weight=49.

The Normality of 0.98%(wV) H2SO4 solution is

Normality=%×10Eq.wtN=0.98×1049N=0.2 Sulphuric acid M.wt=98, E.Weight=49.

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The Normality of 0.98% $(\frac{w}{V})$ H₂SO₄ solution is

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0.2N

0.1N

0.4N

answer is B.

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$\begin{array}{l} Normality = \frac{% \times 10}{Eq . wt} \\ N = \frac{0 .98 \times 10}{49} \\ N = 0 .2 \end{array}$

Sulphuric acid M.wt=98, E.Weight=49.

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The Normality of 0.98%(wV) H2SO4 solution is

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The Normality of 0.98% $(\frac{w}{V})$ H₂SO₄ solution is