The normality of 0.98% ${\displaystyle (w/v)H_{2}S{O}_4}$ solution is

Normality=1000×W/EV

where W denotes the sulphuric acid mass, E the equivalent weight, and V the volume of solution

Because we know that sulphuric acid is a dibasic acid, its Equivalent weight is: = Molecular weight/ 2 = 49.

As a result, Normality = (0.98 x 1000) / (49 x 100)

= 0.2 N

Hence the correct answer is (B) 0.2