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The normality of 9% acetic acid is:

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1.50N

1.67N

2.38N

3.12N

answer is A.

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Detailed Solution

9%(v/w) acetic acid means 9g acetic acid in 100ml water.

Thus, 90g of Acetic acid would be present in 1000ml of water.

60g=1mole of acetic caid.

Moles of acetic acid = given mass/molar mass=9/60=0.15
Thus, 1.5moles present in 1L of water.

i.e. the solution is 1.5N

In case of CH3CO2H,1Nsolution=1Msolution

Thus, normality of 9% acetic acid=1.5N

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