The normality of H2SO4 in the solution obtained on mixing 100 mL of 0.1 M H2SO4 with 50 mL of 0.1 M NaOH is_______×10–1 N. (Nearest Integer)

No. of equivalents of H2SO4=100×0.1×2=20No. of equivalents of NaOH=50×0.1=5No. of equivalents of H2SO4 left =20−5=15⇒150×x=15x=110=0.1N=1×10−1N

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The normality of H₂SO₄ in the solution obtained on mixing 100 mL of 0.1 M H₂SO₄ with 50 mL of 0.1 M NaOH is_______×10^–1 N. (Nearest Integer)

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No. of equivalents of $H_{2} {SO}_{4} = 100 \times 0 .1 \times 2 = 20$

No. of equivalents of $NaOH = 50 \times 0 .1 = 5$

No. of equivalents of $H_{2} {SO}_{4} left = 20 - 5 = 15$

$\begin{array}{l} \Rightarrow 150 \times x = 15 \\ x = \frac{1}{10} = 0 .1 N = 1 \times 10^{- 1} N \end{array}$

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