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Q.

The Novolac polymer has mass of 963g. The number of monomer units present in it are ______

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answer is 9.

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Detailed Solution

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Monomer of novolac is

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In 963g novolac, let the number of monomer units be n. Then, 

n×124=963+n−118⇒124n−18n=945

⇒106n=945⇒n=945106=9

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