The nucleophilicities of $R_{3} C^{-}, R_{2} N^{-}, R O^{-}$ and $F^{-}$ decrease in the order.

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${(C H_{3})}_{3} C^{-} < (C H_{3}) O^{-} > F^{-} > {(C H_{3})}_{2} N^{-}$

${(C H_{3})}_{3} C^{-} > {(C H_{3})}_{2} N^{-} > (C H_{3}) O^{-} > F^{-}$

$F^{-} > (C H_{3}) O^{-} > {(C H_{3})}_{2} N^{-} > {(C H_{3})}_{3} C^{-}$

$(C H_{3}) O^{-} > F^{-} > {(C H_{3})}_{2} N^{-} > {(C H_{3})}_{3} C^{-}$

answer is A.

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Detailed Solution

$\begin{array}{r} {RS}^{-} > {HS}^{-} > {CN}^{-} > I^{-} > {CH}_{3} O^{-} > {OH}^{-} > \\ N_{3}^{-} > {Br}^{-} > {PhO}^{-} > {CH}_{3} {COO}^{-} > \\ {NH}_{3} > {Cl}^{-} > F^{-} > {NO}_{3}^{-} > H_{2} O \end{array}$

Above is order of nucleophilicity.If less electro negative element have negative charge then it is unstable and can donate to other carbon atom easily.

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