The number divisible by 6  is

A natural number is divisible by $6$ if and only if ,it is divisible by both 2 and 3.

Every number of option is divisible by 2

Disability rule of 3

Option A) $2+6+4+5+0=17$ is not divisible by 3

Option B)  $4+6+2+6+1+6=25$ is not divisible by 3

Option C) $2+5+0+0+0=7$is not divisible by 3

Option D) $2+5+5+0=12$ is divisible by 3